Math, asked by vishantgondia, 8 months ago

Factorise : 2x³ - X²-13x - 6​

Answers

Answered by justfor730
0

Answer:

Step-by-step explanation

First use hit and trial method in

2x^3-x^2-13x-6—-(1)

Let x= -2

So (x+2) is a factor of this (1)

Divide(1) by (x+2)

We get (x+2)(2x^2-5x-3)

Now factories 2x^2 -5x-3

2x^2-(6-1)x-3

2x^2-6x+x-3

2x(x-3)+1(x-3)

(X-3)(2x+1)

So (x-3)(2x+1)(x+2) these are the factor of

2x^3-x^2-13x-6

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