Question

factorise 2x³-x²+x-2

Answer 1

Answer:

2x³-x²+x-2

= 2x³-2-x²+x

= 2(x³-1)-x(x-1)

= {2 (x-1) (x²+x+1)} - x(x-1)

= (x-1) ([2 (x²+x+1)] - x)

= (x-1) (2x²+2x+2-x)

= (x-1) (2x²+x+2) [ANSWER]

Answer 2

2x³-x²+x-2

2x²(x-1) +2(x-1)

(2x²+2) + (x-1)

2x²+2=0

x²=-2/2

x²= -1

x=1

x-1=0

x=1