Question

Factorise ; 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz

Answer 1

Answer:

Given

2x2 + y2 + 8z2 - 2√(2xy) + 4√(2yz) - 8xz

= (-√2x)2 + y2 + {2√(2z)}2 - 2{(-√2x)*y} + 2y*{2√(2z)} + 2*(-√2x)*{2√(2z)}

= {-√2x + y + 2√(2z)}2

= {-√2x + y + 2√(2z)}*{-√2x + y + 2√(2z)}

Answered on: 2016/12/30 by ExamFear Share on Facebook Share of TwitterReport Abuse

Answer 2

Answer :

• 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz.

Step-by-step Explanation :

Given that :

• 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz.

To Do :

• Here, we have to factorise it.

Factorising the given equation :

• It can't be factorised because there are no like terms.

.°. The answer is 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz.

°.° The given equation is 2x³ + y³ + 8z³ – 2√ xy + 4√ yz – 8xz and there are no like terms so the answer is the given equation.