Question

Factorise:2y^2+3y+1​

Answer 1

HeRe Is Your Ans ⤵

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2Y² + 3Y + 1 = 0

2Y² + 2Y + 1Y + 1 = 0

2Y(Y + 1) + 1(Y + 1) = 0

Hence , Y = - 1 / 2 And Y = -1

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Answer 2

hello buddy...

2y2+2y+y+1=0

2y(y+1)+1(y+1)=0

(2y+1)(y+1)=0

2y=-1 ,y=-1

y=-1/2, -1