Question

Factorise 2y^2+3y+1
Using splitting the middle term method.

Answer 1

Answer:

${2y}^{2} + (2 + 1)y \: + 1 \\ {2y}^{2} + 2y + y + 1 \\ 2y(y + 1) + 1(y + 1) \\ (y + 1) + (2y + 1).$

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Answer 2

⠀⠀⠀$\huge\underline{ \mathrm{ \red{QueS{\pink{tiOn}}}}}$

Factorise 2y^2+3y+1

Using splitting the middle term method.

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Answer:-

• y = -1

• y = ½

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$\large\underline{ \underline{ \red{ \bold {Given}}}}$

➜ p(y) = 2y² + 3y +1 = 0

$\large\underline{ \underline{ \red{ \bold {To \:Find}}}}$

➥ we need to find the Value of y

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⠀⠀⠀⠀⠀

$\bf\:\underbrace{By \: splitting\:the\: middle\:term}$

➩⠀⠀⠀⠀⠀2y² + 3y + 1

write 3y as a sum.

➩⠀⠀⠀⠀⠀2y² + 2y + y +1

Factor out 2y from the expression.

➩⠀⠀⠀⠀⠀2y (y + 1) + y + 1

Factor out y +1 from the expression.

➩⠀⠀⠀⠀⠀( y + 1 ) ( 2y + 1)

➥⠀⠀⠀⠀${\underline{\boxed{\color{green}\:\bf{\:\:\:y =1\:\:\:}}}}$⠀ or

➥⠀⠀⠀⠀${\underline{\boxed{\color{green}\:\bf{\:\:\:y =\frac{1}{2}\:\:\:}}}}$⠀

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