Question

Factorise: √2y^2 +8y+ 6√2

Answer 1

Answer:Y=-6/√2 and -√2

Step-by-step explanation:

Answer 2

The factorisation of $\sqrt{2} y^{2} +8y+6\sqrt{2}2y2+8y+62 is (\sqrt{2}y+6)(y+\sqrt{2}).(2y+6)(y+2)$

We have,

$\sqrt{2} y^{2} +8y+6\sqrt{2}2y2+8y+62$

To find, the factorisation of

$\sqrt{2} y^{2} +8y+6\sqrt{2}2y2+8y+62 = ?$

$\sqrt{2} y^{2} +8y+6\sqrt{2}2y2+8y+62$

[/tex]=\sqrt{2} y^{2} +2y+6y+6\sqrt{2}[/tex] =2y2+2y+6y+62

$=\sqrt{2} y(y+\sqrt{2})+6(y+\sqrt{2})=2y(y+2)+6(y+2)</p><p>=(\sqrt{2}y+6)(y+\sqrt{2})=(2y+6)(y+2)</p><p>Hence, the factorisation of \sqrt{2} y^{2} +8y+6\sqrt{2}2y2+8y+62 is  (\sqrt{2}y+6)(y+\sqrt{2}).(2y+6)(y+2).$