Question

factorise- 2y^3+2y^2-2y-1​

Answer 1

Step-by-step explanation:

=(2y+1)(y+1)(y-1)

Now Factorizing

2y³+y²-2y-1

= y² (2y + 1) -1 (2y + 1)

= (2y + 1)(y² – 1)

= (2y + 1)(y² – 1²)

= (2y + 1) (y + 1) (y – 1)

By algebraic identity:

a² – b² = (a + b) (a – b)

Therefore,

2y³ + y² – 2y – 1 = (2y + 1) (y + 1) (y-1)