Question

Factorise 2y^3+y^2-2y-1​

Answer 1

Step-by-step explanation:

Let p(y) = 2y3 + y2 − 2y − 1 By trial method, p(1) = 2 ( 1)3 + (1)2 − 2( 1) − 1 = 2 + 1 − 2 − 1= 0 Therefore, y − 1 is a factor of this polynomial. Let us find the quotient on dividing 2y3 + y2 − 2y − 1 by y − 1.

Answer 2

Answer:

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