Math, asked by theandelshow, 4 months ago

factorise 2y-7 2y+7 using suitable identity ​

Answers

Answered by Anonymous
14

\huge\colorbox{orange}{Answer}

(2y - 7)(2y + 7)

it \: is \: in \: the \: form \: of \:  \\ (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

a = 2y \\ b = 7

 ({2y)}^{2}  -  {(7)}^{2}  \\ 4 {y}^{2}  - 49

Answered by nehal12382
3

(2y - 7)(2y + 7) \\ we \: know \: that \\ (a - b)(a + b) = a {}^{2}  - b {}^{2}  \\ here \\ a = 2y \: and \: b = 7 \\ therefore \\ (2y) {}^{2}  - (7) {}^{2}  \\ 4y {}^{2}  - 49

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