factorise 2y cube minus 5y square minus 19y plus 42 AND I NEED FULL ANSWER PLS.
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Here is the solution.Hope it helps you out(BRAINLIEST ANSWER PLS)
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Answer:
(2y-7) (y+3) (y-2)
Step-by-step explanation:
= 2y³-5y²-19y+42
= 2y³+(-4y²-y²)+(2y-21y)+42
= 2y³- 4y²-y²+2y-21y+4
= 2y²(y-2) -y(y-2)-21(y-2)
take (y-2) as common
=[2y²-y-21] (y-2)
split the middle term in [2y²-y-21]
=[(2y²+6y-7y-21)](y-2)
=[2y(y+3)-7(y+3)](y-2)
=(2y-7) (y+3) (y-2)
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