factorise : 2y cube+y sq-2y-1
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Step-by-step explanation:
¤Question
•Factorise:-2y^3+y^2-2y-1
¤Solution:-
》Let p(y)=2y^3+y^2-2y-1
》By trial method ▪
》p(1)=2(1)^3+(1)^2-2(1)-1
》2+1-2-1
》0
》Therefore,y-1 is a factor of this polynimal.
》Let us find the Quotient on dividing
▪Above is the dividing part.
》p(y)-2y^3+y^2-2y-1
》(y-1)(2y^2+3y+1)
》(y-1)(2y^2+2y+y+1)
》(y-1)[2y(y+1)+1(y+1)]
》(y-1)(y+1)(2y+1)
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