Question

Factorise:2y2-22y+48​

Answer 1

Answer:

2y²-22y+48 = 0

2(y²-11y+24) = 0

y²-11y+24 = 0

y²-(8y+3y)+24 = 0

y²-8y-3y+24 =0

y(y-8) -3(y-8) = 0

(y-8)(y-3) = 0

y = 8, y = 3

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