Question

Factorise:2y2+3y+1....


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Answer 1

y=-1,-1/2.

Step-by-step explanation:

first splitting the midterm

2y^2+2y+y+1

then take common value

2y(y+1)+1(y+1).

(y+1)+(2y+1)=0

value of y= -1,-1/2.

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