Factorise
2y2 - 5y - 3
Answers
Answered by
0
Answer:
How to solve your problem
2
2
−
5
−
3
2y^{2}-5y-3
2y2−5y−3
Grouping
1
Use the sum-product pattern
2
2
−
5
−
3
2y^{2}{\color{#c92786}{-5y}}-3
2y2−5y−3
2
2
+
−
6
−
3
2y^{2}+{\color{#c92786}{y}}{\color{#c92786}{-6y}}-3
2y2+y−6y−3
2
Common factor from the two pairs
2
2
+
−
6
−
3
2y^{2}+y-6y-3
2y2+y−6y−3
(
2
+
1
)
−
3
(
2
+
1
)
y(2y+1)-3(2y+1)
y(2y+1)−3(2y+1)
3
Rewrite in factored form
(
2
+
1
)
−
3
(
2
+
1
)
y(2y+1)-3(2y+1)
y(2y+1)−3(2y+1)
(
−
3
)
(
2
+
1
)
(y-3)(2y+1)
(y−3)(2y+1)
Solution
(
−
3
)
(
2
+
1
)
Answered by
0
Answer:
2y² - 5y - 3 = 0
y = (5+- √25 + 24)/4
y = (5+7)/4 or (5-7)/4
y = 3 or -1/2
Hope this helps ☺️
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