Question

Factorise : √2y² + 8y+6√2​

Answer 1

Answer:

please check the attached image.

Answer 2

The factorisation of $\sqrt{2} y^{2} +8y+6\sqrt{2}$ is $(\sqrt{2}y+6)(y+\sqrt{2}).$

Step-by-step explanation:

We have,

$\sqrt{2} y^{2} +8y+6\sqrt{2}$

To find, the factorisation of $\sqrt{2} y^{2} +8y+6\sqrt{2}$ = ?

∴$\sqrt{2} y^{2} +8y+6\sqrt{2}$

$=\sqrt{2} y^{2} +2y+6y+6\sqrt{2}$

$=\sqrt{2} y(y+\sqrt{2})+6(y+\sqrt{2})$

$=(\sqrt{2}y+6)(y+\sqrt{2})$

Hence, the factorisation of $\sqrt{2} y^{2} +8y+6\sqrt{2}$ is  $(\sqrt{2}y+6)(y+\sqrt{2}).$