Question

factorise 2y²-y-1 by middle term splitting​

Answer 1

Answer:

there will be 2 values of Y that are 1,-1/2

Step-by-step explanation:

2y^2-y-1

= 2y^2-2y+y-1

= 2y(y-1)+1(y-1)

= (2y+1)(y-1)

y=-1/2

y=1

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\green{ANSWER:-}$

⏩2y² -y -1 [Factorize]

Write -y as a sum or difference.

→ 2y² +y -2y -1

Factor out y and -1 from the expression.

→y(2y +1)-1(2y+1)

Factor out 2y+1 from the expression.

→ (2y+1)(y-1)

The required factorization....

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Hope it helps...:-)

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