Question

factorise 2y3 -4y2-2y+4
​

Answer 1

Step-by-step explanation:

(y−1)(y+1)(2y+1)

Step-by-step explanation:

Given :2y^3+y^2-2y-12y

3

+y

2

−2y−1

To Find : Factorize

Solution:

2y^3+y^2-2y-12y

3

+y

2

−2y−1

2y^3-2y+y^2-12y

3

−2y+y

2

−1

2y(y^2-1)+y^2-12y(y

2

−1)+y

2

−1

(y^2-1)(2y+1)(y

2

−1)(2y+1)

Identity : a^2-b^2=(a+b)(a-b)a

2

−b

2

=(a+b)(a−b)

(y-1)(y+1)(2y+1)(y−1)(y+1)(2y+1)

Hence 2y^3+y^2-2y-12y

3

+y

2

−2y−1 is (y-1)(y+1)(2y+1)(y−1)(y+1)(2y+1)

Answer 2

Step-by-step explanation:

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