factorise 2y3 -4y2-2y+4
Answers
Answered by
2
Step-by-step explanation:
(y−1)(y+1)(2y+1)
Step-by-step explanation:
Given :2y^3+y^2-2y-12y
3
+y
2
−2y−1
To Find : Factorize
Solution:
2y^3+y^2-2y-12y
3
+y
2
−2y−1
2y^3-2y+y^2-12y
3
−2y+y
2
−1
2y(y^2-1)+y^2-12y(y
2
−1)+y
2
−1
(y^2-1)(2y+1)(y
2
−1)(2y+1)
Identity : a^2-b^2=(a+b)(a-b)a
2
−b
2
=(a+b)(a−b)
(y-1)(y+1)(2y+1)(y−1)(y+1)(2y+1)
Hence 2y^3+y^2-2y-12y
3
+y
2
−2y−1 is (y-1)(y+1)(2y+1)(y−1)(y+1)(2y+1)
Answered by
17
Step-by-step explanation:
ye jo upper wala answer h na ...usko brainlist bna do...
Similar questions