factorise 2y3+5y2+4y+1
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Your question is
2
3
+
5
2
+
4
+
1
2y^{3}+5y^{2}+4y+1
2y3+5y2+4y+1
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1
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Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
(
2
+
2
+
1
)
(
2
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1
)
Answered by
0
Step-by-step explanation:
Factorise 2y3+5y2+4y+1
So
Now
2y3+5y2+4y+1
2y3+5y2=4y+1
2y3+5y2=5y
Base will cone first....
3y2+2y5=5y
6+10=5y
16=5y
Y=16/5....
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