Question

factorise 2y3+y2-2y-1​

Answer 1

Answer:

Here is your answer.......

$2 {y}^{3} + {y}^{2} - 2y - 1 \\ = {y}^{2} (2y + 1) - 1(2y + 1) \\ = (2y + 1)( {y}^{2} - 1) \\ = (2y + 1)(y + 1)(y - 1)$

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Answer 2

Answer:

2y³+y²-2y-1=(y-1)(y+1)(2y+1)

Step-by-step explanation:

Let p(y)=2y³+y²-2y-1

Bytrail,wefindthat,

p(1)=2(1)³+1²-2(1)-1

=2+1-2-1

=0

ByFactor theorem,

(y-1)is afactor ofp(y).

Now,

2y³+y²-2y-1

=2y²(y-1)+3y(y-1)+1(y-1)

=(y-1)(2y²+3y+1)

=(y-1)(2y²+2y+1y+1)

=(y-1)[2y(y+1)+1(y+1)]

=(y-1)(y+1)(2y+1)

Therefore,

2y³+y²-2y-1=(y-1)(y+1)(2y+1)