factorise 3-12(a-b)²
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Answered by
15
Hi,
Problem: 3 - 12(a - b)^2
*** take 3 Common **
= 3[1 - 4(a - b)^2]
= 3[(1)^2 - {2(a - b)}^2]
= 3[(1)^2 - (2a - 2b)^2]
= 3[(1 + 2a - 2b)(1 - 2a + 2b)] <==ANSWER
Since, a^2 - b^2 =(a +b)(a - b)
Hope i helped u :).
Problem: 3 - 12(a - b)^2
*** take 3 Common **
= 3[1 - 4(a - b)^2]
= 3[(1)^2 - {2(a - b)}^2]
= 3[(1)^2 - (2a - 2b)^2]
= 3[(1 + 2a - 2b)(1 - 2a + 2b)] <==ANSWER
Since, a^2 - b^2 =(a +b)(a - b)
Hope i helped u :).
nihma43:
thnksss
Answered by
5
HEY MATE HERE IS YOUR ANSWER‼️
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3( 1 - 4(a - b)2))
3( 12 - [2(a - b)]2 ))
3( 1 + 2( a - b)) ( 1 - (2(a - b))) ]
3[ 1 + 2a - 2b) ( 1 - (2a - 2b)
3(1+ 2a - 2b)(1 -2a + 2b)
Ans: 3(1+ 2a - 2b)(1 -2a + 2b)
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HOPE THIS ANSWER HELPS TO YOU✌️✌️
✴️✴️✴️✴️✴️✴️✴️✴️✴️✴️✴️✴️
〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️
3( 1 - 4(a - b)2))
3( 12 - [2(a - b)]2 ))
3( 1 + 2( a - b)) ( 1 - (2(a - b))) ]
3[ 1 + 2a - 2b) ( 1 - (2a - 2b)
3(1+ 2a - 2b)(1 -2a + 2b)
Ans: 3(1+ 2a - 2b)(1 -2a + 2b)
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HOPE THIS ANSWER HELPS TO YOU✌️✌️
✴️✴️✴️✴️✴️✴️✴️✴️✴️✴️✴️✴️
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