factorise 3-12 (a-b)^2
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3-12 (a-b)^2
0= -9 (a^2+b^2-2ab)
0/-9=a^2+b^2-2ab
0=a^2+b^2-2ab
0=(a-b)(a-b)
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3-12 (a-b)^2
0= -9 (a^2+b^2-2ab)
0/-9=a^2+b^2-2ab
0=a^2+b^2-2ab
0=(a-b)(a-b)
_______☆☆HOPE THE ANSWER HELPS YOU ☆☆____☆☆BE BRAINLY ☆☆
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