factorise (3+23y-8y^2)
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Question :-
Factories it .
→ 3 + 23y - 8y²
Answer :-
→ 3 and -1/8 are factors of this polynomial.
Explanation :-
If we need to factories any Quadratic firstly take it equal to zero and make coefficient of highest degree to positive.
→ 3 + 23y - 8y² = 0
multiply by negative sign on both sides
→ 8y² - 23y - 3 = 0
splitting the middle term
→ 8y² - 24y +y - 3 = 0
→ 8y (y -3) +1(y -3) = 0
→ (y -3)(8y +1) = 0
♣ Case (1) if ,
→ y - 3 = 0
→ y = 3
♣ Case (2) if ,
→ 8y +1 = 0
→ 8y = -1
→y = -1/8
→ 3 and -1/8 are factors of this polynomial.
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