Question

factorise 3(3a+2c)-4b(b+c)​

Answer 1

Answer:

9a^2+6ac-4b^2-4bc

Step-by-step explanation:

3(3a+2c)-4b(b+c)​

9a^2+6ac-4b(b+c)​

9a^2+6ac-4b^2-4bc