Question

factorise 3√3a³+8b³-27c³+18√3abc​

Answer 1

${3 \sqrt{3}a}^{3} + {8b}^{3} - {27c}^{3} + 18 \sqrt{3}abc \\ {( \sqrt{3}a)}^{3} + {(2b)}^{3} + {( - 3c)}^{3} - 3( \sqrt{3}a)(2b)( - 3c) \\ ( \sqrt{3}a + 2b - 3c )( {3a}^{2} + {4b}^{2} + {9c}^{2} - 2 \sqrt{3}ab + 6bc + 3 \sqrt{3}ac)$