factorise 3- 4t - t square
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Solution:
Given. quadratic expression
3-4t-t²
= -(t²+4t-3)
= -(t²+4t+4-4-3)
= -[ (t²+4t+4) - 7 ]
= -[ (t²+2*t*2+2²)- 7 ]
= -[ (t+2)² - (√7)²]
= - [ (t+2+√7)(t+2-√7)]
Therefore,
3-4t-t² = - [ (t+2+√7)(t+2-√7)]
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