factorise 3 - 5 a + 5 b - 12( a- b)
whole square
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3 - 5a + 5b - 12(a-b)²
3 - 5(a-b) - 12(a-b)²
let a-b be x
therefore
3 - 5x - 12x²
3 - 9x + 4x - 12x²
3(1 - 3x) + 4x(1 - 3x)
(3 + 4x)(1 - 3x)
substituting a - b we get
{3 + 4(a-b)}{1 - 3(a-b)}
( 3 + 4a - 4b ) ( 1 - 3a + 3b)
hope it helps
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HOPE THIS HELPS....
ANSWER IS
( 1 - 3a - 3b) ( 4a + 4b +3 )
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