Question

Factorise: 3(6x2 + 5x)2 – 10(6x2 + 5x) - 8​

Answer 1

Let (6x²+5x) be "a"

Hence,

$3 {(6 {x}^{2} + 5x) }^{2} - 10(6 {x}^{2} + 5x) - 8$

$3 {a}^{2} - 10a - 8$

$3 {a}^{2} - 12a + 2a - 8$

$3a(a - 4) + 2(a - 4)$

$(3a + 2)(a - 4)$

Replacing The value of "a"

$(3(6 {x}^{2} + 5x) + 2)(6 {x}^{2} + 5x - 4)$

$(18 {x}^{2} + 15x + 2)(6 {x}^{2} + 5x - 4)$

u'r done!!

Thnx✌️♥️~