factorise 3 - 8(2x - y) + 4(2x - y)^2
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Answer:
♦ ( 4x - 2y - 1 ) ( 4x - 2y - 3 )
Step-by-step explanation:
This question is from the topic "factorisation", which means which is a process of writing an expression in the form of terms which are multiplied together.
Let's factorize the given trinomial...
Let 2x - y = a
Rewriting the given expression again, we have:
- 3 - 8a + 4a²
Taking the coefficient of a² in front,
- 4a² - 8a + 3
As the trinomial is in the form ax² + bx + c, so we will split 8 the coefficient of a into two parts such that the sum of these two parts is equal to 8 and the product of these two parts is equal to product of of 4 and 3.
4a² - 2a - 6a + 3
Now, factorize by grouping method, we get:
- 2a( 2a - 1 ) - 3 ( 2a + 1 )
- ( 2a - 1 ) ( 2a - 3 )
Now, substituting the value of a, we have:
- ( 2(2x - y) - 1 ) ( 2(2x - y) - 3 )
- ( 4x - 2y - 1 ) ( 4x - 2y - 3 )
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