Question

Factorise 3(a-2b)^2 - 2(a-2b) - 8

Answer 1

Question:-

➡ Factorise 3(a - 2b)² - 2(a - 2b) - 8

Solution:-

3(a - 2b)² - 2(a - 2b) - 8

= 3(a - 2b)² - 6(a - 2b) + 4(a - 2b) - 8

= 3(a - 2b){(a - 2b) - 2} + 4(a - 2b - 2)

= (3a - 6b + 4)(a - 2b - 2)

➡ Hence, the factorised form is (3a - 6b + 4)(a - 2b - 2)

Answer 2

Answer:

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Step-by-step explanation:

We have to find such 2 numbers whose sum is -2x and the product is -24

And that numbers are -6x and 4x