Math, asked by pkvortex08, 1 year ago

factorise 3 (a-2b)^2 - 5 (a - 2b)

Answers

Answered by siddhartharao77
169
Given, 3 (a-2b)^2 - 5 (a - 2b)

           = 3(a-2b)^2  - 5 * (a-2b)

          = (a-2b) (3 * (a-2b) + 5 (-1))

          = (a-2b)(3a-6b-5).

Hope this helps!

pkvortex08: yep it helped thanks
Answered by Incredible29
140
Heya user ,
Here is your answer !!

_________

3 ( a - 2b )² - 5 ( a - 2b )

Let ( a - 2b ) be x .

So , 3 ( a - 2b )² - 5 ( a - 2b )
= 3x² - 5x
= x ( 3x - 5 )

Now , putting the value of x , we get ,
x ( 3x - 5 )
= ( a - 2b ) { 3 ( a - 2b ) - 5 }
= ( a - 2b ) ( 3a - 6b - 5 ) [ Answer ] .

_________


Hope it helps !!

Incredible29: plz follow if u lyk my answer
pkvortex08: sure
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