factorise 3 (a-2b)^2 - 5 (a - 2b)
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Answered by
169
Given, 3 (a-2b)^2 - 5 (a - 2b)
= 3(a-2b)^2 - 5 * (a-2b)
= (a-2b) (3 * (a-2b) + 5 (-1))
= (a-2b)(3a-6b-5).
Hope this helps!
= 3(a-2b)^2 - 5 * (a-2b)
= (a-2b) (3 * (a-2b) + 5 (-1))
= (a-2b)(3a-6b-5).
Hope this helps!
pkvortex08:
yep it helped thanks
Answered by
140
Heya user ,
Here is your answer !!
_________
3 ( a - 2b )² - 5 ( a - 2b )
Let ( a - 2b ) be x .
So , 3 ( a - 2b )² - 5 ( a - 2b )
= 3x² - 5x
= x ( 3x - 5 )
Now , putting the value of x , we get ,
x ( 3x - 5 )
= ( a - 2b ) { 3 ( a - 2b ) - 5 }
= ( a - 2b ) ( 3a - 6b - 5 ) [ Answer ] .
_________
Hope it helps !!
Here is your answer !!
_________
3 ( a - 2b )² - 5 ( a - 2b )
Let ( a - 2b ) be x .
So , 3 ( a - 2b )² - 5 ( a - 2b )
= 3x² - 5x
= x ( 3x - 5 )
Now , putting the value of x , we get ,
x ( 3x - 5 )
= ( a - 2b ) { 3 ( a - 2b ) - 5 }
= ( a - 2b ) ( 3a - 6b - 5 ) [ Answer ] .
_________
Hope it helps !!
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