Question

Factorise: 3 (a-2b)^2-5 (a-2b)

Please ans fast

Answer 1

$<b>$ Method 1 :


= >3( a - 2b )² - 5( a - 2b )


[ ( a - 2b ) is common. ]


= > ( a - 2b ) { 3( a - 2b ) - 5 }


= > ( a - 2b ) { 3a - 6b - 5 }


= > ( a - 2b ) ( 3a - 6b - 5 )




Method 2 :



Let ( a - 2b )² = x



= > 3x² - 5z


= > x( 3x - 5 )




Putting the value of x,




= > ( a - 2b ) { 3( a - 2b ) - 5 }


= > ( a - 2b ) { 3a - 6b - 5 }

Answer 2

$\bf \LARGE \it Hey \: User!!!$

given :- 3(a - 2b)² - 5(a - 2b)

= 3 [ (a)² + (2b)² - 2(a)(2b) ] - 5a + 10b
= 3(a² + 4b² - 4ab) - 5a + 10b
= 3a² + 12b² - 12ab - 5a + 10b

$\bf \large \it{Cheers!!}$