Question

Factorise 3-a(4+7a)​

Answer 1

Step-by-step explanation:

Here we have

3- a(4+7a)

= 3- 4a - 7a²

Now let's find the zeroes by splitting

3-4a- 7a²= 0

-(7a²+4a-3) = 0

7a² + 7a-4a -3 = 0

7a(a+1) -1(a+1) = 0

(7a-1) (a+1) = 0

therefore a= 1/7

or a = -1