Question

factorise:3-a (4+7a)​

Answer 1

Answer:

3−a(4+7a)

=3−4a−7a2

=−7a2−4a+3

=−7a2−7a+3a+3

=−7a(a+1)+3(a+1)

=(a+1)(3−7a)

Answer 2

Step-by-step explanation:

3(4+7a)-a(4+7a)=12+21a-4a-7a^2=12+19a-7a^2=-(7a^2-19a-12)