Question

factorise 3 p square + 14 P + 8​

Answer 1

$3 {p}^{2} + 14p + 8 \\ 3 {p}^{2} + 12p + 2p + 8 \\ 3p(p + 4) + 2(p + 4) \\ (p + 4)(3p + 2) \\ p = - 4 \: or \: p = \frac{ - 2}{3}$

Answer 2

$\huge\underline\mathrm{Question-}$

Factorise 3p² + 14p + 8

$\huge\underline\mathrm{Answer-}$

Required factors are : ( p + 4 ) ( 3p + 2 )

$\huge\underline\mathrm{Solution-}$

Given expression : 3p² + 14p + 8

• Sum = 14
• product = 3 × 8 => 24
• factors = (2,12)

By splitting middle term,

$\mapsto$ 3p² + 2p + 12p + 8

$\rule{200}1$

Taking as common,

$\mapsto$ p ( 3p + 2 ) + 4 ( 3p + 2 )

$\mapsto$ ( p + 4 ) ( 3p + 2 )

$\therefore$ Our required factors are : ( p + 4 ) ( 3p + 2 )