Question

factorise 3(x+1)²-10(x+1)(y+1)+8(y+1)²​

Answer 1

Answer:

$3\left(x+1\right)^2-10\left(x+1\right)\left(y+1\right)+8\left(y+1\right)^2\\= 3\left(x^2+2x+1\right)-10\left(x+1\right)\left(y+1\right)+8\left(y+1\right)^2\\= 3\left(x^2+2x+1\right)-10\left(x+1\right)\left(y+1\right)+8\left(y^2+2y+1\right)\\= 3x^2+6x+3-10\left(x+1\right)\left(y+1\right)+8\left(y^2+2y+1\right)\\= 3x^2+6x+3-10xy-10x-10y-10+8\left(y^2+2y+1\right)\\= 3x^2+6x+3-10xy-10x-10y-10+8y^2+16y+8\\= 3x^2-10xy-4x+8y^2+6y+1$

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