Question

factorise 3(x+1)^2+10(x+1)(y+1)+8(y+1)^2​

Answer 1

Answer:

(x+2y+3)(3x+4y+7)

Step-by-step explanation:

3(x+1)^2+10(x+1)(y+1)+8(y+1)^2​

Let x+1=a and y+1=b

then expression is

3a²+10ab+8b²

=3a²+6ab+4ab+8b²

=3a(a+2b)+4b(a+2b)

=(a+2b)(3a+4b)

={ x+1+2(y+1)} {3(x+1)+4(y+1) }

=(x+1+2y+2) (3x+3+4y+4)

=(x+2y+3)(3x+4y+7)