Question

Factorise 32-3(x-4)²​

Answer 1

hey mate plz mark brainliest plzzz

32 - 2 (x - 4)^2

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}= 2 {4 - (x - 4)} {4 + (x - 4)},

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}= 2 {4 - (x - 4)} {4 + (x - 4)},using the identity (a + b)(a - b) = a^2 - b^2

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}= 2 {4 - (x - 4)} {4 + (x - 4)},using the identity (a + b)(a - b) = a^2 - b^2= 2 (4 - x + 4) (4 + x - 4)

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}= 2 {4 - (x - 4)} {4 + (x - 4)},using the identity (a + b)(a - b) = a^2 - b^2= 2 (4 - x + 4) (4 + x - 4)= 2 (8 - x) (x)

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}= 2 {4 - (x - 4)} {4 + (x - 4)},using the identity (a + b)(a - b) = a^2 - b^2= 2 (4 - x + 4) (4 + x - 4)= 2 (8 - x) (x)= 2 x (8 - x),

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}= 2 {4 - (x - 4)} {4 + (x - 4)},using the identity (a + b)(a - b) = a^2 - b^2= 2 (4 - x + 4) (4 + x - 4)= 2 (8 - x) (x)= 2 x (8 - x),which is the required factorization.

32 - 2 (x - 4)^2= 2 {16 - (x - 4)^2}= 2 {4^2 - (x - 4)^2}= 2 {4 - (x - 4)} {4 + (x - 4)},using the identity (a + b)(a - b) = a^2 - b^2= 2 (4 - x + 4) (4 + x - 4)= 2 (8 - x) (x)= 2 x (8 - x),which is the required factorization.#MarkAsBrainliest

Answer 2

Answer:

232

Step-by-step explanation:

32-3(×-4)×2 = 32-3=29=29×4=116×2=232