Question

factorise 32 (a+b)² - 18 (a-b)²​

Answer 1

Given:-

$\sf 32(a+b)² - 18(a-b)²$

Formula Used:-

$\sf (a+b)²=a²+2ab+b²$

$\sf (a-b)²=a²-2ab+b²$

Solution:-

$\sf 32(a+b)²-18(a-b)²$

$\sf 32[a²+2ab+b²]-18[a²-2ab+b²]$

$\sf 32a²+64ab+32b²-18a²+36ab-18b²$

$\sf 32a²-18a²+64ab+36ab+32b²-18b²$

$\sf 14a²+100ab+14b²$

$\sf\red{ 14a²+100ab+14b²}$