Question

Factorise (324a²b² — 72abc + 4c²)
a) 4 (9a²b + c)²
b) 4 ( 9ab-c)²
c) 4 (9a²b–c)²
d) 4 -(9ab +c)²​

Answer 1

Answer:

OPTION B IS CORRECT

Step-by-step explanation:

$(324 {a}^{2} {b}^{2} - 72abc + 4 {c}^{2} ) = 4(81 {a}^{2} {b}^{2} - 18abc - {c}^{2} ) \\ \\ = 4 {(9a b- c)}^{2} .$