factorise
32a^3
+ 108b^3
.
Answers
Answered by
11
Answer:
32a^3+108b^3
take 4 common from both of them
which becomes,
4(8a^3+27b^3)
next,
8a^3=(2a)^3
27b^3=(3b)^3
4[(2a)^3+(3b)^3]
ok
mark as brainliest plzzzz
Similar questions