Question

Factorise


32a_x3 – 86233 - 4a´y3 + b2y3​

Answer 1

(The sign ^ stands for square)

By grouping,

(32a^2x^3-8b^2x^3)-(4a^2y^3-b^2y^3)

Now factorise

8x^3(4a^2-b^2)-y^3(4a^2-b^2)

Now take common,

Then we get,

(4a^2-b^2)(8x^3-y^3)

Hope you got it!

Answer 2

Step-by-step explanation:

$32 {a}^{2} {x}^{3} - 8 {b}^{2} {x}^{3} - 4 {a}^{2} {y}^{3} + {b}^{2} {y}^{3} \\ 8 {x}^{3} (4 {a}^{2} - 8 {b}^{2} ) - {y}^{3}(4 {a}^{2} - {b}^{3} ) \\ (8 {x}^{3} - {y}^{3} )(4 {a}^{2} - 8 {b}^{2} )$

HOPE IT HELPS.........