factorise 343a3-512b3
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We know that,
a³ – b³ = (a – b) (a² + b² + ab)
343a3 – 512b3 = (7a)³ – (8b)³
Here, a = 7a and b = 8b
Now, substituting in the above formula, we get
(7a)³ – (8b)³ = (7a – 8b) [(7a)² + (7a)(8b) + (8b)²]
= (7a – 8b) (49a² + 56ab + 64b²)
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