factorise 343y^3+729z^3
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Answer:
factorise:- 343y³+729z³
= (7y)³+(9z)³
formula :- a³+b³= (a+b) (a²+b²-ab)
= (7y+9z) [(7y)²+(9z)²-7y×9z}
= (7y+9z) (49y²+81z²-63yz) answer
thank You
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