Factorise: 36a^2 – (p-q)^2
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2
Answer:
The factorisation of 36a^2+36a+936a
2
+36a+9 is (6a+3)(6a+3).(6a+3)(6a+3).
Step-by-step explanation:
We have,
36a^2+36a+936a
2
+36a+9
To find, the factorisation of 36a^2+36a+936a
2
+36a+9 = ?
∴ 36a^2+36a+936a
2
+36a+9
=(6a)^2+2(6a)(3)+3^{2}=(6a)
2
+2(6a)(3)+3
2
=(6a+3)^{2}=(6a+3)
2
[ ∵ (a+b)^{2}=a^{2}+2ab+b^{2}(a+b)
2
=a
2
+2ab+b
2
=(6a+3)(6a+3)=(6a+3)(6a+3)
Hence, the factorisation of 36a^2+36a+936a
2
+36a+
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Step-by-step explanation:
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