Math, asked by uday4681, 2 months ago

Factorise: 36a^2 – (p-q)^2

Answers

Answered by nikhilrajgone2008
2

Answer:

The factorisation of 36a^2+36a+936a

2

+36a+9 is (6a+3)(6a+3).(6a+3)(6a+3).

Step-by-step explanation:

We have,

36a^2+36a+936a

2

+36a+9

To find, the factorisation of 36a^2+36a+936a

2

+36a+9 = ?

∴ 36a^2+36a+936a

2

+36a+9

=(6a)^2+2(6a)(3)+3^{2}=(6a)

2

+2(6a)(3)+3

2

=(6a+3)^{2}=(6a+3)

2

[ ∵ (a+b)^{2}=a^{2}+2ab+b^{2}(a+b)

2

=a

2

+2ab+b

2

=(6a+3)(6a+3)=(6a+3)(6a+3)

Hence, the factorisation of 36a^2+36a+936a

2

+36a+

Answered by cutebrainlystar
1

Step-by-step explanation:

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