Question

factorise_
36c²-(5a + b)²​

Answer 1

Step-by-step explanation:

using theorem a²-b² =(a+b)(a-b)

where a= 6c and b =(5a + b)

36c²-(5a + b)²

=(6c)²-(5a + b)²

=[6c+(5a + b)].[6c-(5a + b)]

=[6c+5a + b][6c-5a - b]

=(6c+5a + b)(6c-5a - b)

Ans

Answer 2

$\text{ \purple{ \huge{solution}}}$

Formula used,

$\mathcal{ \blue{ \boxed{ {a}^{2} - {b}^{2} = (a + b)(a - b)}}}$

$\sf{36c {}^{2} -(5a + b) {}^{2} } \\ \sf{ = (6c) {}^{2} - (5a + b) {}^{2}} \\ \sf{ = (6c + 5a + b)(6c - 5a - b)} \\ \sf{ \orange{ = (5a + b + 6c)(6c - 5a - b )}}$