Question

factorise 36x^-121y^​

Answer 1

Answer:

Enter a problem...

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Algebra

 

Factor 36x^2-121y^2

36x2−121y236x2-121y2

Rewrite 36x236x2 as (6x)2(6x)2.

(6x)2−121y2(6x)2-121y2

Rewrite 121y2121y2 as (11y)2(11y)2.

(6x)2−(11y)2(6x)2-(11y)2

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=6xa=6x and b=11yb=11y.

(6x+11y)(6x−(11y))(6x+11y)(6x-(11y))

Multiply 1111 by −1-1.

Answer 2

Answer:

Changes made to your input should not affect the solution:

(1): "^-121" was replaced by "^(-121)".

STEP

1

:

Equation at the end of step 1

(22•32x(-121)) • y

STEP

2

:

Final result :

(22•32x(-121)y)