Question

Factorise : (3a-1)^2 -6a+2

Answer 1

please mark as brainliest answer.

Answer 2

hello Frnd

here is your answer

Given as

$(3 a - 1)^{2} - 6a + 2 \\ \\ apply \: {a}^{2} + {b}^{2} - 2ab = 0\\ \\ 9 {a}^{2} + 1 - 6a - 6a + 2 = 0 \\ 9 {a}^{2} - 12a + 3 = 0 \\ \\ taking \: 3 \: as \: common \\ \\ 3 {a }^{2} - 4a +1 \\ 3 {a}^{2} - 3a - a + 1 = 0\\ 3a(a - 1) - 1(a - 1) \\ (3a - 1)(a - 1) = 0 \\ 3a - 1 = 0 \: \: \: \: \: \: \: or \: \: \: (a - 1) = 0 \\ \\ a = \frac{1}{3} \: \: \: \: \: \: \: or \: a = 1$

hope it helps you
jerri