factorise 3a^2+4ab+b^2-2ac-c^2
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3a2+3ab+ab+b2-c(2a+c)
=3a (a+b)+b (a+b)-c(2a+c)
=(a+b)(3a+b)-c(2a+c)
=3a (a+b)+b (a+b)-c(2a+c)
=(a+b)(3a+b)-c(2a+c)
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Answer:
3a^2 + 3ab + ab+ b^2 - c (2a + c)
3a (a + b ) + b ( a + b ) - c ( 2a + c )
(a+b) ( 3a + b) - c ( 2a + c )
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