factorise (3a+2b)^3
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Answer:
(3a+2b)³
we know
(a+b)³=a³+3a²b+3ab²+b²
here
a=3a
b=2b
therefore the equation is
(3a)³+3×(3a)²×2b+3×3a×+(2b)²+(2b)³
27a³+6b×9a²+9a×4b²+8b³
=27a³+54a²b+36ab²+8b³
hope it helps
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