Question

Factorise 3a^2bc+6ab^2c+9abc^2 with complete process and step by step explaination

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Answer 1

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Answer 2

Let us first find the HCF of all the terms of the given polynomial 3a

2

bc+6ab

2

c+9abc

2

by factoring the terms as follows:

3a

2

bc=3×a×a×b×c

6ab

2

c=3×2×a×b×b×c

9abc

2

=3×3×a×b×c×c

Therefore, HCF=3×a×b×c=3abc

Now, we factor out the HCF from each term of the polynomial 3a

2

bc+6ab

2

c+9abc

2

as shown below:

3a

2

bc+6ab

2

c+9abc

2

=3abc(a+2b+3c)

Hence, 3a

2

bc+6ab

2

c+9abc

2

=3abc(a+2b+3c).